NECO Chemistry Answers and Questions – Complete Solution 2022/2023.
NECO Chemistry Questions and Answers: Below is the National Examination Council (NECO) Chemistry Answers and Questions – Complete Solution 2022/2023.
We will update you with NECO materials, for NECO Chemistry questions and answers 2022. The questions will be set from the Chemistry practical specimens that will be provided during the exam.
Recommended NECO Chemistry Questions and Answers 2022
Chemistry NECO Questions and Answers will be publish here. The Theory, OBJ and Practical. practical apparatus include the tools that will be needed to carry out the practical and the chemicals (Different acids and Bases) needed for the practical.
NECO Chemistry Questions and Answers – Objective & Essay – Chemistry › 10:00am – 1:00pm – Monday 25th July.
(i) KAl(SO₄)₂. 12H₂O
Number of moles of sodium reascted = reacting mass/molar mass
Number of moles of oxygen reacted = (1/4) x Number of sodium
= 1/4 x (3.6/23)
Reacting mass of oxygen = Number of moles x molar mass
= 0.03913 x (16×2)
Air in gaseous form is first passed through caustic soda to remove CO₂. It is compressed and cooled until ut becomes a liquid at -200°C. It is then led to a fractionating column. On distillation, Nitrogen which has a lowet boiling point of -196°C is evolced first leaving behind Oxygen in liquid form. Further heating converts the liquid to a gas at -183°C.
(i) It is used for combustion
(ii) It is used for artificial respiration
This is because room temperature is warmer
(i) Methyl orange
An ion is an atom or molecule which has a net electric charge due to the loss or gain of one or more electrons.
HCl gas doesn’t contain ions
(i) Noble gases: Neon, Helium
(ii) Halogens: Iodine, Fluorine
(iii) Alkaline earth metals: Calcium, Magnesium
Halogens attain stable octet configuration by accepting an electron from donors Group I elements.
A sol is a colloid where solid particles are dispersed in liquid medium.
(i) Acid-base titrations are used to determine the percentage purity of a substance
(ii) Acid-base titrations are important to determine the number of water molecules in a hydrate.
A molar solution of a compound contains one mole or the molar mass of the compound in one dm³ of the solution.
(i) Identification of gases
(ii) Identification of acidic and metallic radicals
(i) Purification of bauxite
(ii) Electrolysis of alumina
This is because of the presence of copper which is a transition metal
(i) Methanamide is a liquid while the rest amides are crystalline solids
(ii) Melting points and boiling points of aides are much higher than expected.
(i) Heavy chemicals are produced in very large quantities in industries While fine chemicals are produced in small quantities for specific purposes
(ii) Heavy chemicals are in a crude state While fine chemicals are purified.
(i) Million’s reagent
(ii) Feeling’s solution
Graham’s law of diffusion states that at a constant temperature and pressure the rate of diffusion of a gas is inversely proportional to the square root of its density.
RO₂/RCH₄ = √(MCH₄/MO₂)
5/(200/t) = √[(12+4)/(16×2)]
5t/200 = √16/32
t/40 = 1/√2
t = 40/√2
t = (40/√2) × (√2/√2)
t = 20√2 seconds
Time taken = 28.28 seconds.
A hydrocarbon is an organic compound composed only of two elements carbon and hydrogen.
They are unsaturated compounds
(i) Decrease in pressure
(ii) Finely divided zinc
(iii) Removal of hydrogen gas
(i) Electrovalent compounds conduct electricity While covalent compounds do not.
(ii) Electrovalent compounds dissolve in polar solvents While covalent compounds dissolve in non-polar solvents.
(i) High melting and boiling points
(ii) Exist mainly as solids at room temperature
(i) Ammonia, NH₃
(ii) Hydrogen chloride gas, HCl
(i) Potassium hexacyanoferrate(II)
(ii) It is a complex salt
(i) Wrought iron
(ii) Cast iron
2H₂ + O₂ →2H₂O
2 : 1 : 2
40cm³ : 20cm³ : 40cm³
(50 – 40) (20 – 20)
= 10cm³ = 0cm³ = 40cm³
Total residual volume = 10 + 40
I – C₂H₂OH + H₂SO₄ —>C₂H₅HSO₄ + H₂O
II – C₂H₅HSO₄ —> C₂H₄ +H₂SO₄
(i) They incompletely filled d-orbitals
(ii) They exhibit variable oxidation state
(i) It is used in making aeroplane parts due to its tensile strength
(ii) It is used in making window frames because it cannot be easily oxidised
A white precipitate is formed with evolution of brown gas
(i) Hydrogen bond
(ii) Covalent bond
H₂SO₄ + 2NaOH —> Na₂SO₄ +2H₂O
CaVa/CbVb = Na/NB
Va = CbVbna/Can
Va = 0.1×25×1/0.5×2
Va = 2.5cm³
Rate of a chemical reaction is defined as the number of moles of reactant converted or product formed per unit time.
Mass of CaCO3 = 3g
Molar mass of CaCO3= 100g/mol
No. of moles = 3/100 = 0.03
Time = 2×60 = 120s
Rate of reaction = No. of moles/Time
= 0.03/120 = 2.5 × 10-⁴
(i) They are more resistant to corrosion
(ii) They are more durable
(iii) They have lower melting point
2Pb(NO₃)₂ —> 2PbO + 4NO₂ +O₂
I =Hard water=
(i)It has better taste than soft water
(ii) It can be supplied in lead pipes as it does not dissolve lead
II =Soft water=
(i) It does not deposit scale in boilers and fur in kettles
(ii) It does not waste soap
I – CO
II – SO₂
I – Hardness
II – Lustre appearance
III – Conductivity
IV – Ability to absorb
4.3/2.12 = 142+18x/142
2.12(142+18x)/2.12 = 4.3*142/2.12
142+18x = 288
18x = 288-142
x = 146/18
x = 8
Each candidates should be supplied with the following, labelled An, Bn, Xn and Yn; where ’n’ is the candidate’s serial number.
* 150cm³ of trioxonitrate(v) acid solution in a bottle labelled “An”. The acid solution which should be the same for all candidates will contain 9.50cm³ of concentrated trioxonitrate(v) acid per dm³ of solution.
See Also: NECO Time Table
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